A) 8
B) 0
C) 4
D) 2
Correct Answer: A
Solution :
Expression,\[\frac{1}{(1+\cos \theta )}+\frac{1}{(1-\cos \theta )}\] \[=\frac{1-\cos \theta +1+\cos \theta }{(1+\cos \theta )(1-\cos \theta )}=\frac{2}{1-{{\cos }^{2}}\theta }\] \[=\frac{2}{{{\sin }^{2}}\theta }=\frac{2}{{{\sin }^{2}}30{}^\circ }\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,[\because \theta =30{}^\circ ]\] \[=\frac{2}{{{\left( \frac{1}{2} \right)}^{2}}}=8\]
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