| In this, one term in the number series is wrong. Find out the wrong term. |
| 1, 5, 9, 16, 25, 37, 49 |
A) 16
B) 9
C) 25
D) 37
Correct Answer: A
Solution :
The series is alternate one. \[\begin{array}{*{35}{r}} 1 & 9 & 25 & 49 \\ \downarrow & \downarrow & \downarrow & \downarrow \\ {{1}^{2}} & {{3}^{2}} & {{5}^{2}} & {{7}^{2}} \\ \end{array}\] and \[\begin{array}{*{35}{r}} 5 & [16] & 37 \\ \downarrow & \downarrow & \downarrow \\ {{2}^{2}}+1 & {{4}^{2}}+1 & {{6}^{2}}+1 \\ \end{array}\] \[\therefore \] Required letter = 8 So, the wrong number is 16. In place of 16, it should be \[{{4}^{2}}+1=17\] in the series.
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