A) 86
B) 88
C) 120
D) 90
Correct Answer: A
Solution :
\[{{(2)}^{2}}+{{(2)}^{2}}+{{(4)}^{2}}+{{(3)}^{2}}=4+4+16+9=33\] \[{{(3)}^{2}}+{{(2)}^{2}}+{{(5)}^{2}}+{{(4)}^{2}}=9+4+25+16=54\] \[{{(6)}^{2}}+{{(5)}^{2}}+{{(4)}^{2}}+{{(3)}^{2}}=36+25+16+9=(86)\]
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