question_answer

A number when divided by three consecutive numbers 9, 11, 13 leaves the remainders 8, 9 and 8 respectively. If the order of divisors is reversed, the remainders will be

A)  8, 9, 8 

B)  9, 8, 8       

C)  10, 1, 6           

D)  10, 8, 9

Correct Answer: C

Solution :

Least number = z \[x=13\times 1+8=21\]  \[y=11x+9=11\times 21+9=240\] \[z=9y+8=9\times 240+8=2168\] Dividing 2168 by 13, 11, 9. We get the remainders = 10, 1, 6