A) \[\frac{1}{2}\]
B) \[\sqrt{3}\]
C) 1
D) 1
Correct Answer: C
Solution :
\[\because \] \[{{\sin }^{2}}38{}^\circ +{{\cos }^{2}}38{}^\circ \] \[={{\sin }^{2}}38{}^\circ +(1-{{\sin }^{2}}38{}^\circ )=1\]You need to login to perform this action.
You will be redirected in
3 sec