A) \[\frac{x}{4{{x}^{2}}+1}\]
B) \[\frac{4x+1}{x}\]
C) \[\frac{1}{4{{x}^{3}}+x}\]
D) None of these
Correct Answer: D
Solution :
\[A+\frac{1}{4}=\frac{4{{x}^{2}}+1}{x}+\frac{x}{4{{x}^{2}}+1}\]. \[=\frac{{{(4{{x}^{2}}+1)}^{2}}+{{x}^{2}}}{x(4{{x}^{2}}+1)}=\frac{16{{x}^{4}}+9{{x}^{2}}+1}{4{{x}^{3}}+x}\]
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