A) 999999
B) 988899
C) 989898
D) 998889
Correct Answer: A
Solution :
[a] Given P=99 Then \[P\,\,({{P}^{2}}+3p+3)\] \[=p\,\,({{(p+1)}^{2}}+p+2)\] \[=99\,\,({{(99+1)}^{2}}+101)\] \[=99\times (10000+101)\] \[=999999\]
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