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Railways Sample Paper RRB (Group D) Sample Test Paper-9

  • question_answer
    The sum of four numbers is 48. When 5 and 1 are added to the first two; and 3 & 7 are subtracted from the 3rd & 4th, the numbers will be equal. The numbers are

    A)  4, 12, 12, 20    

    B)  5, 11, 13, 19

    C)  6, 10, 14, 18    

    D)  9, 7, 15, 17

    Correct Answer: C

    Solution :

    [c] Let four numbers are a, b, c, d, then a+b+c+d=48               ... (i) And a+5=b+1              ... (ii) Or, \[a=b-4\]                  ... (iii) And \[c-\,3=d-\,7\]          ... (iv) \[c=d-4\]                       ... (v) Substituting equation (iii) and (v) in equation (i) we get \[b-\,4+b+d-\,4+d=48\] \[b+d=28\] But we know, \[b+1=d-\,7\] \[\therefore \,\,\,b=d-\,8\] Substituting in equation (vi) we get \[d-\,8\ne d=28\] d=18 Solving this way we get a\[6,\,\,b=10,\,\,c=14\,\,and\,\,d=18\]


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