A) 60
B) 45
C) 40
D) 30
Correct Answer: A
Solution :
[a] (A+B)'s 1 day's work =\[\frac{1}{15}\] B's 1 day's work = \[\frac{1}{20}\] \[\therefore \]A's l day?s work \[=\frac{1}{15}-\,\frac{1}{20}=\frac{4-3}{60}=\frac{1}{60}\] \[\therefore \]A alone will do the work in 60 days Alternate Method: Work efficiency of A + B: working efficiency of \[B=\frac{1}{Time\,of(A+b)}:\frac{1}{Time\,of\,B}=\frac{1}{15}:\frac{1}{20}=4:3\] Total work unit = efficiency of worker \[\times \] time of worker \[=15\times 4=60\] efficiency of \[A=4-\,3=1\] Required time \[=\frac{60}{1}=60\]daysYou need to login to perform this action.
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