A) 5
B) 5.5
C) 6
D) 6.5
Correct Answer: A
Solution :
[a] \[A=p{{\left( 1+\frac{R}{100} \right)}^{T}}\] \[\Rightarrow \,\,\,\frac{1102.50}{1000}={{\left( 1+\frac{r}{100} \right)}^{2}}\] \[\Rightarrow \,\,\,\frac{11025}{10000}={{\left( 1+\frac{r}{100} \right)}^{2}}\] \[\Rightarrow \,\,\,{{\left( \frac{105}{100} \right)}^{2}}={{\left( 1=\frac{r}{100} \right)}^{2}}\] \[\Rightarrow \,\,\,1+\frac{r}{100}=\frac{105}{100}\] \[\Rightarrow \,\,\,\frac{r}{100}=\frac{105}{100}-\,1\] \[\Rightarrow \,\,\,r=5%\]
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