A) 1
B) 2
C) 7
D) 17
Correct Answer: B
Solution :
[b] If the first divisor is a multiple of second divisor. Then, remainder by the second divisor. \[1\,\,\,light\,\,year=9.46\times {{10}^{15}}m\]Remainder\[=21\div 19=2\]
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