A) 03
B) 0.5
C) 0.8
D) 0.9
Correct Answer: C
Solution :
[c] If 0.5=a and 0.3=b then, Expression \[=\frac{{{a}^{3}}+{{b}^{3}}}{{{a}^{2}}-\,ab+{{b}^{2}}}\] \[=\frac{(a+b)\,\,({{a}^{2}}-ab+{{b}^{2}})}{{{a}^{2}}-ab+{{b}^{2}}}=a+b=0.5+0.3=0.8\]
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