Railways Sample Paper RRB (Group D) Sample Test Paper-3

  • question_answer
    A solid cylinder having radius of base as 7 cm and length as 20 cm is bisected from its height to get two identical cylinders. What will be the percentage increase in the total surface area?

    A)  29.78  

    B)  25.93

    C)  27.62  

    D)  32.83

    Correct Answer: B

    Solution :

    [b] Here, Radius of cylinder=7 cm Height of cylinder=20 cm \[\therefore \] Total surface area of cylinder \[2\pi rh+2\pi {{r}^{2}}\] \[=2\times \frac{22}{7}\times 7\times 20+2\times \frac{22}{7}\times 7\times 7\] \[=880+308=1188\,\,c{{m}^{2}}\] When cylinder is cutting along height, two new Cylinders are generated-radius of new cylinder=7cm height of new cylinder=10cm \[\therefore \] Total surface area of new cylinder \[=2\pi rh+2\pi {{r}^{2}}\] \[\Rightarrow \,\,\,2\times \frac{22}{7}\times 7\times 10+2\times \frac{22}{7}\times 7\times 7\] \[\Rightarrow \,\,\,440+308\] \[=748\times 2=1496\,\,c{{m}^{2}}\] \[{{F}_{2}}\,to\,{{I}_{2}}\]Total surface area of two new cylinders \[=748\times 2=1496\,\,c{{m}^{2}}\] \[\therefore \]Percentage increase in surface area \[=\left( \frac{(1496-\,1188)}{1188}\times 100 \right)%=25.93%\]


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