A) 2
B) \[-\,1\]
C) 0
D) 1
Correct Answer: C
Solution :
[c] \[\frac{a}{b}+\frac{b}{a}=2\] \[\Rightarrow \,\frac{{{a}^{2}}+{{b}^{2}}}{ab}=2\] \[\Rightarrow \frac{{{(a-\,b)}^{2}}+2ab}{ab}=2\] \[{{(a-\,b)}^{2}}=2ab-\,2ab\] \[{{(a-\,b)}^{2}}=0\] \[a-\,b=0\]You need to login to perform this action.
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