A) 8
B) 12
C) 20
D) 32
Correct Answer: C
Solution :
[c] According to question \[26<\sqrt{709}<27\] \[Now,\,\,{{(27)}^{2}}=729\] \[\therefore 729-709=20\] \[\therefore \]20 must be added to 709 to make it a perfect square.
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