A) 296
B) 295
C) 290
D) 228
Correct Answer: C
Solution :
[c] Let the two numbers be x and y. \[\therefore \,\,\,x+y=24\] And, xy=143 \[\therefore \,\,\,{{x}^{2}}+{{y}^{2}}={{(x+y)}^{2}}-\,2xy\] \[={{(24)}^{2}}-\,2\times 143=576-\,286=290\]
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