A) 6
B) 30
C) \[\sqrt{15}\]
D) 15
Correct Answer: D
Solution :
[d] \[2\sqrt{x}=\frac{\sqrt{5}+\sqrt{3}}{\sqrt{5}-\,\sqrt{3}}-\,\frac{\sqrt{5}-\,\sqrt{3}}{\sqrt{5}+\sqrt{3}}\] \[=\frac{{{(\sqrt{5}+\sqrt{3})}^{2}}-\,{{(\sqrt{5}-\,\sqrt{3})}^{2}}}{(\sqrt{5}-\,\sqrt{3)\,\,(\sqrt{5}+\sqrt{3})}}=\frac{4.\sqrt{5}.\sqrt{3}}{5-\,3}=2\sqrt{15}\]\[\therefore \,\,\,2\sqrt{x}=2\sqrt{15}\Rightarrow \,\,\,x=15\]
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