• # question_answer If ${{x}^{2}}-\,3x+1=0,\,\,(x\ne 0),$then the value of $x+\frac{1}{x}$ is A)  1                     B)  0 C)  3                     D)  2

[c] ${{x}^{2}}-\,3x+1=0$ Dividing Equation by x $x-\,3+\frac{1}{x}=0$ $x+\frac{1}{x}=3$