Railways Sample Paper RRB (Group D) Sample Test Paper-12

  • question_answer
    If \[{{x}^{2}}-\,3x+1=0,\,\,(x\ne 0),\]then the value of \[x+\frac{1}{x}\] is

    A)  1                    

    B)  0

    C)  3                    

    D)  2

    Correct Answer: C

    Solution :

    [c] \[{{x}^{2}}-\,3x+1=0\] Dividing Equation by x \[x-\,3+\frac{1}{x}=0\] \[x+\frac{1}{x}=3\]


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