A) \[351\,\,c{{m}^{2}}\]
B) \[256\,\,c{{m}^{2}}\]
C) \[265\,\,c{{m}^{2}}\]
D) \[315\,\,c{{m}^{2}}\]
Correct Answer: A
Solution :
[a] Let length=l, breadth=b, height=h. L+b+h=24 (given) ... (i) Diagonal of parallellopiped=15 cm \[\sqrt{{{l}^{2}}+{{b}^{2}}+{{h}^{2}}}=15\,\,or\,\,{{l}^{2}}+{{b}^{2}}+{{h}^{2}}=225\] Squaring eqn. (i) on both sides \[{{l}^{2}}+{{b}^{2}}+{{h}^{2}}+2lb+2bh+2hl=576\] \[2\,\,(lb+bh+hl)=576-\,225=351\] \[[\therefore \]Surface area of parallellopiped \[=2\,\,(lb+bh+hl)]\]
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