A) \[\frac{n+1}{2}\]
B) \[\frac{{{n}^{2}}\,\,(n+1)}{2}\]
C) \[2\,\,(n+1)\]
D) \[\frac{n\,\,(n+1)}{2}\]
Correct Answer: A
Solution :
[a] Arithmetic mean of first 'n' natural number \[=\frac{Sum\,\,of\,\,'n'\,\,natura\operatorname{l}\,\,number}{Number\,\,of\,\,observation}=\frac{(n)\,\,(n+1)}{2\times n}=\frac{n+1}{2}\]
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