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Railways Sample Paper RRB (Group D) Sample Test Paper-11

  • question_answer
    The least multiple of 13 which when divided by 4, 5, 6, 7 leaves remainder 3 in each case is

    A)  3780   

    B)  3783

    C)  2520               

    D)  2522

    Correct Answer: B

    Solution :

    [b] LCM of 4, 5, 6 and 7=420 \[\therefore \]Required number = 420k+3 which is exactly divisible by 13. \[=32\times l3k+4k+3\] Hence, 4k+3 should be divisible by 13 for some value of k. For k=9, 4k+3=39 which is divisible by 13. \[\therefore \] Required number=\[420\times 9+3=3783\]


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