question_answer

If diagonals of a rhombus are 16 cm and 30 cm. then what is the perimeter (in cm) of the rhombus?

A)  32       

B)  64

C)  34                   

D)  68

Correct Answer: D

Solution :

[d] Let side of rhombus be x By Pythagorean Theorem, \[{{x}^{2}}={{(15)}^{2}}+{{(8)}^{2}}\] \[{{x}^{2}}=225+64=289\] \[\therefore x=\sqrt{289}=17\,\,cm\] \[\therefore \]Perimeter of rhombus \[=4\times \]side \[=4\times 17\] =68 cm