A) \[\frac{71}{190}\]
B) \[\frac{121}{190}\]
C) \[\frac{91}{190}\]
D) \[\frac{93}{190}\]
Correct Answer: C
Solution :
Total possible outcomes \[=20{{c}_{2}}\,=\frac{20\,\,\,\,\,19}{1\,\,\,\,\,\,\,2}=190\] Total favourable outcomes \[={{7}_{C1}}\,\,\,\,{{13}_{C1}}\,\,=\,\,7\,\,\,13\,\,=91\] \[\therefore \] Required probability \[=\frac{91}{190}\]
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