A) \[14\frac{2}{7}\] days
B) \[33\frac{1}{3}\] days
C) \[18\frac{3}{4}\] days
D) 10 days
Correct Answer: D
Solution :
6M= 20W 4M= 5W 28M+15W 35W+15W= 50W therefore, work done by 28M and 15W is \[\left( \frac{20\,\,\,25}{50} \right)=\]10days
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