A) \[{{a}^{3}}+{{b}^{3}}+{{c}^{3}}\]
B) \[{{a}^{2}}bc+{{b}^{2}}ca+{{c}^{3}}ab\]
C) \[3abc\]
D) \[-3abc\]
Correct Answer: D
Solution :
\[{{a}^{2}}(b+c)+{{b}^{2}}(c+a)+c2(a+b)\] \[{{a}^{2}}b+{{a}^{2}}c+{{b}^{2}}c+{{b}^{2}}a+{{c}^{2}}a+{{c}^{2}}b\] = \[ab(a+b)+bc(b+c)+ca(c+a)\] = \[ab(-c)+bc(-a)+ca(-b)\] = \[-3abc\]
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