A) 15 days
B) 10 days
C) 16 days
D) 12 days
Correct Answer: B
Solution :
(A + B)s 1 days work \[=\frac{1}{10};\] (B + C)s 1 days work \[=\frac{1}{15};\] (A + C)s 1 days work \[=\frac{1}{30}\] Adding, we get: 2(A + B + C)s 1 days Work \[=\frac{1}{10}+\frac{1}{15}+\frac{1}{30}=\frac{6}{30}=\frac{1}{5}\] (A + B + C)s 1 days work \[=\frac{1}{10}\] So, A, B and C together can complete the work in 10 days.
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