A) 9
B) 12
C) 13
D) 8
Correct Answer: D
Solution :
Let the numbers are x, y. \[x-y=3\] ...(1) \[{{x}^{2}}-{{y}^{2}}=39\] \[\Rightarrow \] \[(x-y)\,\,(x+y)=39\] \[\Rightarrow \] \[x+y=13\] ??(2) Adding eqn (1) and (2) \[x+y+x-y=16\] \[\Rightarrow \] \[x=8\] \[\therefore \] \[y=5\] Hence, 8 is the larger number.You need to login to perform this action.
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