A) \[420\,c{{m}^{2}}\]
B) \[275\,c{{m}^{2}}\]
C) \[351\,c{{m}^{2}}\]
D) \[378\,c{{m}^{2}}\]
Correct Answer: C
Solution :
Let length, breadth and height of parallelepiped be l, b and h respectively \[l+b+h=24\,cm\] \[\sqrt{{{l}^{2}}+{{b}^{2}}+{{h}^{2}}}=15\,cm\Rightarrow {{l}^{2}}+{{b}^{2}}+{{h}^{2}}=225c{{m}^{2}}\]\[{{(l+b+h)}^{2}}-2(lb+hb+lh)=225\] \[{{(24)}^{2}}-225=2(lb+bh+hl)\] \[351=2(lb+bh+hl)\] Total surface area is \[351\text{ }c{{m}^{2}}.\]
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