A) 8%
B) \[9\frac{1}{2}%\]
C) 9%
D) \[9\frac{1}{11}%\]
Correct Answer: D
Solution :
Let initial volume = 100 Volume after increase \[=100\times \frac{110}{100}=110\] So, decrease \[=\frac{110-100}{110}\times 100\] \[=\frac{10}{110}\times 100=9\frac{1}{11}%\]You need to login to perform this action.
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