A) 2
B) 3
C) 4
D) 5
Correct Answer: C
Solution :
[c] Let number be x \[\therefore \] \[\frac{21-x}{38-x}=\frac{55-x}{106-x}\] \[2226-21x-106x+{{x}^{2}}=2090-38x-55x+{{x}^{2}}\]34x = 136 x = 4 \[\therefore \] The number is 4You need to login to perform this action.
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