A) 8
B) 7
C) 6
D) 12
Correct Answer: C
Solution :
[c] Let the ratio be k \[\therefore \] \[a+b=6k,\,\,b+c=7k,\,\,c+a=8k\] \[\Rightarrow \] \[(a+b)+(b+c)+(c+a)=6k+7k+8k\] \[\Rightarrow \] \[2(a+b+c)=21k\] \[\Rightarrow \] \[k=\frac{2\times 14}{21}=\frac{4}{3}\] \[\therefore \] \[c=(a+b+c)-(a+b)\] \[=14-6\times \frac{4}{3}\] =14 ? 8 = 6You need to login to perform this action.
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