| What was the day of the week on 5th June, 2002? |
A) Wednesday
B) Saturday
C) Friday
D) Monday
E) None of these
Correct Answer: A
Solution :
| Period upto 5th June, 2002 |
| = (Year 2001 + Period from 1.1.2002 to 5.6.2002) |
| \[\therefore \]Odd days in 1600 yr = 0 |
| Odd days in 400 yr = 0 |
| Odd days in 1 ordinary year = 1 |
| Odd days in year 2001\[=(0+0+1)=1\] |
| Number of days from 1.1.2002 to 5.6,2002 |
| January + February + March + April + May + June |
| \[=31+28+31+30+31+5\] |
| = 156 days = 22 weeks + 2 days = 2 odd days |
| \[\therefore \]Total number of odd days \[=(1+2)=3\] |
| Hence, the required day is Wednesday. |
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