question_answer

The maximum peak to peak voltage of an AM wave is 16 m V and the minimum peak to peak voltage is 8 m V What is the modulation factor?

Answer:

                                    Clearly, \[{{E}_{\max }}=16/2=8\,mV\]                         \[{{E}_{\min }}=8/2=4\,mV\] Therefore, modulation factor,             \[m=\frac{{{E}_{\max }}-{{E}_{\min }}}{{{E}_{\max }}+{{E}_{\min }}}\] \[\Rightarrow \]   \[m=\frac{8-4}{8+4}=\frac{4}{12}=\frac{1}{3}=0.33\] \[\Rightarrow \]   m = 0.33