A) 33
B) 32
C) 31
D) 30
Correct Answer: D
Solution :
[d] Two digits numbers which are divisible by 3 are 12, 15, 18, 21, 24, ____, 99. Now, this is an A.P where a = 12, d = 3 and \[{{a}_{n}}=99.\] As we know, \[{{a}_{n}}=a+(n-1)d\] \[\Rightarrow \] \[99=12+\left( n-1 \right)3=9+3n\] \[\Rightarrow \] 90 = 3n \[\Rightarrow \] n = 30. Hence, there are 30 numbers which are divisible by 3.
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