A) 7
B) 5
C) 3
D) 2.5
Correct Answer: C
Solution :
[c] Let the whole number be x According to question \[x+20=\frac{69}{x}\] \[\Rightarrow \] \[{{x}^{2}}+20x=69\] \[\Rightarrow \] \[{{x}^{2}}+20x-69=0\] \[\Rightarrow \] \[{{x}^{2}}+23x-3x-69=0\] \[\Rightarrow \] \[x(x+23)-3(x+23)=0\] \[\Rightarrow \] \[(x+23)(x-3)=0\] \[\therefore \] x=3 or \[-23,\] Hence, 3 is only whole number.You need to login to perform this action.
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