A) 5 \[\Omega \]
B) 10 \[\Omega \]
C) 20 \[\Omega \]
D) 200 \[\Omega \]
Correct Answer: C
Solution :
[c] \[{{A}_{1}}{{I}_{1}}={{A}_{2}}{{I}_{2}}\] or\[{{A}_{2}}=\frac{{{A}_{1}}{{I}_{1}}}{{{I}_{2}}}\] \[={{A}_{1}}\times \frac{20}{40}\] \[=\frac{{{A}_{1}}}{2}\] We have, \[{{R}_{1}}=\rho \frac{{{I}_{1}}}{{{A}_{1}}}\] \[{{R}_{2}}=\rho \frac{{{I}_{2}}}{{{A}_{2}}}\] \[=P\frac{2{{I}_{1}}}{{{A}_{1/2}}}=4\left( \frac{\rho {{I}_{1}}}{{{A}_{1}}} \right)=(4\times 5)\Omega =20\Omega \]
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