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NTSE Sample Paper NTSE SAT Practice Test-7

  • question_answer
    If (x-k) is a common factor of \[q{{x}^{2}}+2x+p\]and \[q{{x}^{2}}+x+r\] then k has the value

    A) \[r+p\]              

    B) p-q

    C) \[2r-p\]              

    D) r-p

    Correct Answer: D

    Solution :

    [d] Since (x -k) is a factor of both expressions, so \[q{{k}^{2}}+2k\text{ + }p=0\]and \[q{{k}^{2}}+k+r=0\]and on subtraction, we get \[k=r-p.\]


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