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NTSE Sample Paper NTSE SAT Practice Test-7

  • question_answer
    If\[{{2}^{2x-1}}=\frac{1}{{{8}^{x-3}}}\]then the value of x is

    A) 3                                 

    B) 2

    C) 0                                 

    D) -2

    Correct Answer: B

    Solution :

    [b] \[{{2}^{2x-1}}=\frac{1}{{{8}^{x-3}}}\Rightarrow {{2}^{2x-1}}={{2}^{-3(x-3)}}\] \[\therefore \,\,\,2x-1=-\,3\,(x-3)\] \[\Rightarrow \,\,5x=10\,\,orx=2\]


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