A) \[1.6\times {{10}^{-12}}A\]
B) \[1.6\times {{10}^{12}}A\]
C) \[1.6\times {{10}^{-26}}A\]
D) \[1.6\times {{20}^{26}}\]
Correct Answer: A
Solution :
[a] \[I=\frac{q}{t}\] \[=\frac{ne}{t}\] \[=\frac{{{10}^{7}}\times 1.6\times {{10}^{-19}}}{1}\] \[=1.6\times {{10}^{-12}}A\]
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