A) 1
B) 2
C) 3
D) ? 1
Correct Answer: A
Solution :
[a] \[x\left\{ \frac{b+c}{(c-a)(a-b)}+\frac{c+a}{(a-b)(b-c)}+\frac{a+b}{(b-c)(c-a)} \right\}\] \[x\left\{ \frac{{{b}^{2}}-{{c}^{2}}}{(a-b)(b-c)(c-a)}+\frac{{{c}^{2}}-{{a}^{2}}}{(a-b)(b-c)(c-a)}+\frac{{{a}^{2}}-{{b}^{2}}}{(a-b)(b-c)(c-a)} \right\}\]\[x\left\{ \frac{{{b}^{2}}-{{c}^{2}}+{{c}^{2}}-{{a}^{2}}+{{a}^{2}}-{{b}^{2}}}{(a-b)(b-c)(c-a)} \right\}=x{}^\circ =1\]
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