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NTSE Sample Paper NTSE SAT Practice Test-20

  • question_answer
    If \[ab-b+1=0\]and\[bc-c+1=0\], then the value of (ca-a) is

    A) -1        

    B) 0

    C) 1                                 

    D) 2

    Correct Answer: A

    Solution :

    [a] \[ab-b+1=0\Rightarrow abc-bc+c=0\] \[bc-c+1=0\Rightarrow \text{ }abc\,\,-\text{ }ac+a=0\] On subtraction, we have \[ac-a=-\text{ }bc+c=-1\Rightarrow ac-\text{ }a=-\text{ }1.\]                   


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