NTSE Sample Paper NTSE SAT Practice Test-19

  • question_answer
    A body of mass 100 g is rotating in a circular path of radius r with constant speed. The work done in one complete revolution is

    A) \[100\,r\,J\]                   

    B) \[\left( \frac{r}{100} \right)J\]

    C) \[\left( \frac{100}{r} \right)J\]      

    D)          zero

    Correct Answer: D

    Solution :

    [d] Work done \[=\text{ }F\text{ }S\text{ }cos\text{ }\theta \text{ =}FS\text{ }cos\text{ }90{}^\circ \text{ }=\text{ }0\] \[\therefore \text{ }cos\text{ }90{}^\circ =0\] You must also note that the work done by the centripetal force is zero.


You need to login to perform this action.
You will be redirected in 3 sec spinner