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NTSE Sample Paper NTSE SAT Practice Test-19

  • question_answer
    If \[x(x+y+z)=9,y(xy+z)=16\]and\[z(x+y+z)=144\], then the value of x is

    A) \[\frac{9}{5}\]                          

    B) \[\frac{9}{7}\]

    C) \[\frac{9}{13}\] 

    D) \[\frac{16}{13}\]

    Correct Answer: C

    Solution :

    [c] Adding the there equations, we have \[{{(x+y+z)}^{2}}=169\Rightarrow x+y+z=13\] \[\therefore \,\,x=\frac{9}{13}\]  


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