A) 10.
B) 2 0
C) 50.
D) 80
Correct Answer: A
Solution :
[a] \[R=\frac{\rho \ell }{A}\] \[{{R}^{'}}=\frac{\rho {{\ell }^{'}}}{{{A}^{'}}}\] \[=\frac{\rho (\ell /2)}{2A}\] \[=\frac{1}{4}(R)=\frac{1}{4}\times 4\Omega \] \[=1\Omega \]
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