A) F
B) 2F
C) 4F
D) \[\frac{F}{4}\]
Correct Answer: A
Solution :
[a] \[F=\frac{k{{q}_{1}}{{q}_{2}}}{{{r}^{2}}}\] \[F=\frac{(2{{q}_{1}})\times (2{{q}_{2}})}{{{(2r)}^{2}}}\] \[=\frac{4(k{{q}_{1}}{{q}_{2}})}{4{{r}^{2}}}\] \[=\frac{k{{q}_{1}}{{q}_{2}}}{{{r}^{2}}}\] =F
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