NTSE Sample Paper NTSE SAT Practice Test-18

  • question_answer
    Given that \[{{10}^{\text{o}\text{.48}}}=x,{{10}^{\text{o}\text{.70}}}=y\]and \[{{x}^{z}}={{y}^{2}},\]then the value of z is close to

    A) 1.45                             

    B) 1.88

    C) 2.9 

    D) 3.7

    Correct Answer: C

    Solution :

    [c]\[{{x}^{Z}}={{y}^{2}}\,\,\,\,\Rightarrow \,\,\,{{10}^{0.48}}{{)}^{Z}}={{({{10}^{0.70}})}^{2}}\] \[\Rightarrow \,\,\,0.48Z=0.70\times 2\]             \[\Rightarrow \,\,\,Z=\frac{140}{48}=2.9(approx)\]                       


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