A) 5 days
B) 6 days
C) 10days
D) \[10\frac{1}{2}\]days
Correct Answer: C
Solution :
[c] In 3 days work done by B and C \[=3\times \left( \frac{1}{9}\times \frac{1}{12} \right)\] \[=\frac{7}{12}\] Remaining work to be finished by \[A=1-\frac{7}{12}=\frac{5}{12}\] \[\therefore \] A can do it in \[24\times \frac{5}{12}\] days i.e. in 10 days.
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