A) \[33{}^\circ ,\text{ }44{}^\circ ,\text{ }55{}^\circ \]
B) \[{{36}^{\text{o}}},{{48}^{\text{o}}},{{60}^{\text{o}}}\]
C) \[39{}^\circ ,52{}^\circ ,\text{ }65{}^\circ \]
D) \[42{}^\circ ,\text{ }56{}^\circ ,\text{ }70{}^\circ \]
Correct Answer: B
Solution :
[b] \[\angle ADP\text{ }=\text{ }x+z\]and \[\angle PAD\text{ }-\text{ }\angle DCQ\text{ }=\text{ }x\] In \[\Delta APB,\text{ }\angle x+\left( \angle x+\angle z \right)+y=180{}^\circ \] \[\Rightarrow 3k+3k+5k+4k=180{}^\circ ,\text{ }So\text{ }k=12{}^\circ \] \[\therefore \,\,x,y,z=36{}^\circ ,48{}^\circ ,60{}^\circ \]
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