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NTSE Sample Paper NTSE SAT Practice Test-13

  • question_answer
    If \[x=\frac{a}{b+c},y=\frac{b}{c+a},z=\frac{c}{a+b}\]then the value of \[{{(x+1)}^{-1}}+{{(y+1)}^{-1}}+{{(z+1)}^{-1}}\]is

    A) 1                                 

    B) 2

    C) a+b+c             

    D) \[\frac{1}{2}\]

    Correct Answer: B

    Solution :

    [b] \[1+x=1+\frac{a}{b+c}=\frac{a+b+c}{b+c}\] \[\Rightarrow \frac{1}{1+x}=\frac{b+c}{a+b+c}\] etc.


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