A) 7 ; 5
B) 5 : 7
C) 7 : 3
D) 3 : 7
Correct Answer: A
Solution :
[a] \[{{S}_{1}}=\frac{a}{2}(2\times 4-1)\] \[=\frac{7a}{2}\] Alsno, \[{{S}_{2}}=\frac{a}{2}(2\times 3-1)\] \[=\frac{5a}{2}\] So, \[\frac{{{S}_{1}}}{{{S}_{2}}}=\frac{7a}{\frac{2}{\frac{5a}{2}}}\] \[=\frac{7}{5}\]
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